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4119113 is a prime number
BaseRepresentation
bin1111101101101001001001
321202021100202
433231221021
52023302423
6224141545
750004035
oct17555111
97667322
104119113
112363829
1214678b5
13b12b5b
147931c5
15565728
hex3eda49

4119113 has 2 divisors, whose sum is σ = 4119114. Its totient is φ = 4119112.

The previous prime is 4119109. The next prime is 4119119. The reversal of 4119113 is 3119114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3523129 + 595984 = 1877^2 + 772^2 .

It is a cyclic number.

It is not a de Polignac number, because 4119113 - 22 = 4119109 is a prime.

It is a Sophie Germain prime.

It is an Ulam number.

It is a Curzon number.

It is equal to p291008 and since 4119113 and 291008 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (4119119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2059556 + 2059557.

It is an arithmetic number, because the mean of its divisors is an integer number (2059557).

Almost surely, 24119113 is an apocalyptic number.

It is an amenable number.

4119113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4119113 is an equidigital number, since it uses as much as digits as its factorization.

4119113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108, while the sum is 20.

The square root of 4119113 is about 2029.5598044896. The cubic root of 4119113 is about 160.3003862187.

Subtracting from 4119113 its reverse (3119114), we obtain a palindrome (999999).

The spelling of 4119113 in words is "four million, one hundred nineteen thousand, one hundred thirteen".