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4119713336341 is a prime number
BaseRepresentation
bin111011111100110010000…
…011001100110000010101
3112120211200220110021211001
4323330302003030300111
51014444133103230331
612432323054143301
7603432223402321
oct73746203146025
915524626407731
104119713336341
111349184861079
125665177b1b31
1323b6447a4325
14103576584981
157226abd8561
hex3bf320ccc15

4119713336341 has 2 divisors, whose sum is σ = 4119713336342. Its totient is φ = 4119713336340.

The previous prime is 4119713336203. The next prime is 4119713336447. The reversal of 4119713336341 is 1436333179114.

4119713336341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3486342480625 + 633370855716 = 1867175^2 + 795846^2 .

It is a cyclic number.

It is not a de Polignac number, because 4119713336341 - 223 = 4119704947733 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4119713336291 and 4119713336300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4119713336741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2059856668170 + 2059856668171.

It is an arithmetic number, because the mean of its divisors is an integer number (2059856668171).

Almost surely, 24119713336341 is an apocalyptic number.

It is an amenable number.

4119713336341 is a deficient number, since it is larger than the sum of its proper divisors (1).

4119713336341 is an equidigital number, since it uses as much as digits as its factorization.

4119713336341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 489888, while the sum is 46.

The spelling of 4119713336341 in words is "four trillion, one hundred nineteen billion, seven hundred thirteen million, three hundred thirty-six thousand, three hundred forty-one".