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41200300041 = 313733433347
BaseRepresentation
bin100110010111101110…
…101011000000001001
310221100022122002121120
4212113232223000021
51133334234100131
630532133225453
72655660525555
oct462756530011
9127308562546
1041200300041
111652254a24a
127b99a92289
133b67950484
141dcbb78865
151112081496
hex997bab009

41200300041 has 4 divisors (see below), whose sum is σ = 54933733392. Its totient is φ = 27466866692.

The previous prime is 41200300033. The next prime is 41200300103. The reversal of 41200300041 is 14000300214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41200300041 - 23 = 41200300033 is a prime.

It is a super-3 number, since 3×412003000413 (a number of 33 digits) contains 333 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (41200300021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6866716671 + ... + 6866716676.

It is an arithmetic number, because the mean of its divisors is an integer number (13733433348).

Almost surely, 241200300041 is an apocalyptic number.

It is an amenable number.

41200300041 is a deficient number, since it is larger than the sum of its proper divisors (13733433351).

41200300041 is a wasteful number, since it uses less digits than its factorization.

41200300041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13733433350.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 41200300041 its reverse (14000300214), we get a palindrome (55200600255).

The spelling of 41200300041 in words is "forty-one billion, two hundred million, three hundred thousand, forty-one".

Divisors: 1 3 13733433347 41200300041