Base | Representation |
---|---|
bin | 111011111101001010010… |
… | …111111111111111111101 |
3 | 112120212202100101012221121 |
4 | 323331022113333333331 |
5 | 1020001002042123201 |
6 | 12432431353230541 |
7 | 603445310264524 |
oct | 73751227777775 |
9 | 15525670335847 |
10 | 4120121442301 |
11 | 1349374163127 |
12 | 566610402451 |
13 | 23b6ab1c3347 |
14 | 1035b48594bb |
15 | 7229194d9a1 |
hex | 3bf4a5ffffd |
4120121442301 has 4 divisors (see below), whose sum is σ = 4120128536832. Its totient is φ = 4120114347772.
The previous prime is 4120121442289. The next prime is 4120121442319. The reversal of 4120121442301 is 1032441210214.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4120121442301 - 221 = 4120119345149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4120121440301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2590045 + ... + 3866338.
It is an arithmetic number, because the mean of its divisors is an integer number (1030032134208).
Almost surely, 24120121442301 is an apocalyptic number.
It is an amenable number.
4120121442301 is a deficient number, since it is larger than the sum of its proper divisors (7094531).
4120121442301 is an equidigital number, since it uses as much as digits as its factorization.
4120121442301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7094530.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 4120121442301 its reverse (1032441210214), we get a palindrome (5152562652515).
The spelling of 4120121442301 in words is "four trillion, one hundred twenty billion, one hundred twenty-one million, four hundred forty-two thousand, three hundred one".
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