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412012243 is a prime number
BaseRepresentation
bin11000100011101…
…100111011010011
31001201021101112201
4120203230323103
51320433342433
6104514504031
713132021606
oct3043547323
91051241481
10412012243
111a162a995
12b5b95017
1367489036
143ca1033d
1526287a7d
hex188eced3

412012243 has 2 divisors, whose sum is σ = 412012244. Its totient is φ = 412012242.

The previous prime is 412012241. The next prime is 412012259. The reversal of 412012243 is 342210214.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 412012243 - 21 = 412012241 is a prime.

Together with 412012241, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 412012243.

It is not a weakly prime, because it can be changed into another prime (412012241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206006121 + 206006122.

It is an arithmetic number, because the mean of its divisors is an integer number (206006122).

Almost surely, 2412012243 is an apocalyptic number.

412012243 is a deficient number, since it is larger than the sum of its proper divisors (1).

412012243 is an equidigital number, since it uses as much as digits as its factorization.

412012243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

The square root of 412012243 is about 20298.0847126028. The cubic root of 412012243 is about 744.1092565827.

Adding to 412012243 its reverse (342210214), we get a palindrome (754222457).

The spelling of 412012243 in words is "four hundred twelve million, twelve thousand, two hundred forty-three".