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41203004014121 is a prime number
BaseRepresentation
bin10010101111001010100100…
…11010101111111000101001
312101212222011012012211222012
421113211102122233320221
520400032223011422441
6223344222043205305
711451550564331315
oct1127452232577051
9171788135184865
1041203004014121
1112146106673464
124755502816835
1319cb571340b01
14a26343972b45
154b6bb84e09eb
hex2579526afe29

41203004014121 has 2 divisors, whose sum is σ = 41203004014122. Its totient is φ = 41203004014120.

The previous prime is 41203004014099. The next prime is 41203004014223. The reversal of 41203004014121 is 12141040030214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 41108871024400 + 94132989721 = 6411620^2 + 306811^2 .

It is a cyclic number.

It is not a de Polignac number, because 41203004014121 - 210 = 41203004013097 is a prime.

It is not a weakly prime, because it can be changed into another prime (41203004014621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20601502007060 + 20601502007061.

It is an arithmetic number, because the mean of its divisors is an integer number (20601502007061).

Almost surely, 241203004014121 is an apocalyptic number.

It is an amenable number.

41203004014121 is a deficient number, since it is larger than the sum of its proper divisors (1).

41203004014121 is an equidigital number, since it uses as much as digits as its factorization.

41203004014121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 41203004014121 its reverse (12141040030214), we get a palindrome (53344044044335).

The spelling of 41203004014121 in words is "forty-one trillion, two hundred three billion, four million, fourteen thousand, one hundred twenty-one".