41211030350041 has 4 divisors (see below), whose sum is σ = 41487614446500. Its totient is φ = 40934446253584.

The previous prime is 41211030350033. The next prime is 41211030350089. The reversal of 41211030350041 is 14005303011214.

41211030350041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 27134764482816 + 14076265867225 = 5209104^2 + 3751835^2 .

It is a cyclic number.

It is not a de Polignac number, because 41211030350041 - 2³ = 41211030350033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41211030349988 and 41211030350015.

It is not an unprimeable number, because it can be changed into a prime (41211030350741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138292048006 + ... + 138292048303.

It is an arithmetic number, because the mean of its divisors is an integer number (10371903611625).

Almost surely, 2^{41211030350041} is an apocalyptic number.

It is an amenable number.

41211030350041 is a deficient number, since it is larger than the sum of its proper divisors (276584096459).

41211030350041 is a wasteful number, since it uses less digits than its factorization.

41211030350041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 276584096458.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 41211030350041 its reverse (14005303011214), we get a palindrome (55216333361255).

The spelling of 41211030350041 in words is "forty-one trillion, two hundred eleven billion, thirty million, three hundred fifty thousand, forty-one".