412111031 has 2 divisors, whose sum is σ = 412111032. Its totient is φ = 412111030.

The previous prime is 412111013. The next prime is 412111043. The reversal of 412111031 is 130111214.

Together with previous prime (412111013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 412111031 - 2¹⁰ = 412110007 is a prime.

It is a super-2 number, since 2×412111031² = 339671003743765922, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 412110997 and 412111015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (412111081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206055515 + 206055516.

It is an arithmetic number, because the mean of its divisors is an integer number (206055516).

Almost surely, 2^412111031 is an apocalyptic number.

412111031 is a deficient number, since it is larger than the sum of its proper divisors (1).

412111031 is an equidigital number, since it uses as much as digits as its factorization.

412111031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 412111031 is about 20300.5179983172. The cubic root of 412111031 is about 744.1687234167.

Adding to 412111031 its reverse (130111214), we get a palindrome (542222245).

The spelling of 412111031 in words is "four hundred twelve million, one hundred eleven thousand, thirty-one".