41212104333133 has 4 divisors (see below), whose sum is σ = 41213113312320. Its totient is φ = 41211095353948.

The previous prime is 41212104333017. The next prime is 41212104333139. The reversal of 41212104333133 is 33133340121214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41212104333133 - 2⁴⁵ = 6027732244301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41212104333095 and 41212104333104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41212104333139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504428323 + ... + 504510016.

It is an arithmetic number, because the mean of its divisors is an integer number (10303278328080).

Almost surely, 2^{41212104333133} is an apocalyptic number.

It is an amenable number.

41212104333133 is a deficient number, since it is larger than the sum of its proper divisors (1008979187).

41212104333133 is a wasteful number, since it uses less digits than its factorization.

41212104333133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1008979186.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 41212104333133 its reverse (33133340121214), we get a palindrome (74345444454347).

The spelling of 41212104333133 in words is "forty-one trillion, two hundred twelve billion, one hundred four million, three hundred thirty-three thousand, one hundred thirty-three".