Base | Representation |
---|---|
bin | 1011111111101010000… |
… | …01010110011010101001 |
3 | 1110101210020022121111211 |
4 | 11333311001112122221 |
5 | 23223021430240001 |
6 | 513155305153121 |
7 | 41530013565121 |
oct | 5776501263251 |
9 | 1411706277454 |
10 | 412132665001 |
11 | 14986a166172 |
12 | 67a5a48b7a1 |
13 | 2cb30112665 |
14 | 15d39675c81 |
15 | aac1b22351 |
hex | 5ff50566a9 |
412132665001 has 4 divisors (see below), whose sum is σ = 413116275600. Its totient is φ = 411149054404.
The previous prime is 412132664981. The next prime is 412132665023. The reversal of 412132665001 is 100566231214.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 412132665001 - 237 = 274693711529 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (412132665041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 491804671 + ... + 491805508.
It is an arithmetic number, because the mean of its divisors is an integer number (103279068900).
Almost surely, 2412132665001 is an apocalyptic number.
It is an amenable number.
412132665001 is a deficient number, since it is larger than the sum of its proper divisors (983610599).
412132665001 is an equidigital number, since it uses as much as digits as its factorization.
412132665001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 983610598.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 412132665001 its reverse (100566231214), we get a palindrome (512698896215).
The spelling of 412132665001 in words is "four hundred twelve billion, one hundred thirty-two million, six hundred sixty-five thousand, one".
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