Base | Representation |
---|---|
bin | 111011111110010110101… |
… | …001100101010110001111 |
3 | 112121000001112022120221020 |
4 | 323332112221211112033 |
5 | 1020011112141321033 |
6 | 12433202345205223 |
7 | 603522106334646 |
oct | 73762651452617 |
9 | 15530045276836 |
10 | 4121401120143 |
11 | 134997054001a |
12 | 566908a90813 |
13 | 23b853364378 |
14 | 1036967aa35d |
15 | 72318e776b3 |
hex | 3bf96a6558f |
4121401120143 has 32 divisors (see below), whose sum is σ = 5631296385792. Its totient is φ = 2680510060800.
The previous prime is 4121401120097. The next prime is 4121401120147. The reversal of 4121401120143 is 3410211041214.
It is a happy number.
4121401120143 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4121401120143 - 26 = 4121401120079 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4121401120147) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8573553 + ... + 9041493.
It is an arithmetic number, because the mean of its divisors is an integer number (175978012056).
Almost surely, 24121401120143 is an apocalyptic number.
4121401120143 is a deficient number, since it is larger than the sum of its proper divisors (1509895265649).
4121401120143 is a wasteful number, since it uses less digits than its factorization.
4121401120143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 468455.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 4121401120143 its reverse (3410211041214), we get a palindrome (7531612161357).
The spelling of 4121401120143 in words is "four trillion, one hundred twenty-one billion, four hundred one million, one hundred twenty thousand, one hundred forty-three".
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