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412230013001 = 4110054390561
BaseRepresentation
bin1011111111110101101…
…00101101000001001001
31110102001000111101212022
411333322310231001021
523223221340404001
6513213103454225
741532305203412
oct5777264550111
91412030441768
10412230013001
1114990a106164
1267a86bb7375
132cb47338021
1415d48576809
15aaca45111b
hex5ffad2d049

412230013001 has 4 divisors (see below), whose sum is σ = 422284403604. Its totient is φ = 402175622400.

The previous prime is 412230012959. The next prime is 412230013003. The reversal of 412230013001 is 100310032214.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 40192230400 + 372037782601 = 200480^2 + 609949^2 .

It is a cyclic number.

It is not a de Polignac number, because 412230013001 - 218 = 412229750857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (412230013003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5027195240 + ... + 5027195321.

It is an arithmetic number, because the mean of its divisors is an integer number (105571100901).

Almost surely, 2412230013001 is an apocalyptic number.

412230013001 is a gapful number since it is divisible by the number (41) formed by its first and last digit.

It is an amenable number.

412230013001 is a deficient number, since it is larger than the sum of its proper divisors (10054390603).

412230013001 is a wasteful number, since it uses less digits than its factorization.

412230013001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10054390602.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 412230013001 its reverse (100310032214), we get a palindrome (512540045215).

The spelling of 412230013001 in words is "four hundred twelve billion, two hundred thirty million, thirteen thousand, one".

Divisors: 1 41 10054390561 412230013001