Base | Representation |
---|---|
bin | 10010101111110001111010… |
… | …00001110101111100101111 |
3 | 12101221222122210200002110111 |
4 | 21113320331001311330233 |
5 | 20400403444210002203 |
6 | 223402033240120451 |
7 | 11453226060262252 |
oct | 1127707501657457 |
9 | 171858583602414 |
10 | 41224120000303 |
11 | 12154062036409 |
12 | 4759616466127 |
13 | 1a00557ca58a6 |
14 | a27388159099 |
15 | 4b75021ee26d |
hex | 257e3d075f2f |
41224120000303 has 8 divisors (see below), whose sum is σ = 41236361290800. Its totient is φ = 41211880277568.
The previous prime is 41224120000267. The next prime is 41224120000351. The reversal of 41224120000303 is 30300002142214.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41224120000303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41224120000363) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 53292325 + ... + 54060337.
It is an arithmetic number, because the mean of its divisors is an integer number (5154545161350).
Almost surely, 241224120000303 is an apocalyptic number.
41224120000303 is a deficient number, since it is larger than the sum of its proper divisors (12241290497).
41224120000303 is a wasteful number, since it uses less digits than its factorization.
41224120000303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 783881.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 41224120000303 its reverse (30300002142214), we get a palindrome (71524122142517).
The spelling of 41224120000303 in words is "forty-one trillion, two hundred twenty-four billion, one hundred twenty million, three hundred three", and thus it is an aban number.
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