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41225131002403 is a prime number
BaseRepresentation
bin10010101111110011110010…
…10010100000101000100011
312101222002021021001022121201
421113321321102200220203
520400413032014034103
6223402321433302031
711453263114535245
oct1127717122405043
9171862237038551
1041225131002403
1112154530794237
124759858b64917
131a0068959579a
14a2744252c095
154b7560d5551d
hex257e794a0a23

41225131002403 has 2 divisors, whose sum is σ = 41225131002404. Its totient is φ = 41225131002402.

The previous prime is 41225131002359. The next prime is 41225131002431. The reversal of 41225131002403 is 30420013152214.

It is an a-pointer prime, because the next prime (41225131002431) can be obtained adding 41225131002403 to its sum of digits (28).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41225131002403 - 225 = 41225097447971 is a prime.

It is a super-2 number, since 2×412251310024032 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (41225131002103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20612565501201 + 20612565501202.

It is an arithmetic number, because the mean of its divisors is an integer number (20612565501202).

Almost surely, 241225131002403 is an apocalyptic number.

41225131002403 is a deficient number, since it is larger than the sum of its proper divisors (1).

41225131002403 is an equidigital number, since it uses as much as digits as its factorization.

41225131002403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 41225131002403 its reverse (30420013152214), we get a palindrome (71645144154617).

The spelling of 41225131002403 in words is "forty-one trillion, two hundred twenty-five billion, one hundred thirty-one million, two thousand, four hundred three".