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41230241341 is a prime number
BaseRepresentation
bin100110011001100000…
…111000111000111101
310221102101222021100121
4212121200320320331
51133414420210331
630535123054541
72656503161152
oct463140707075
9127371867317
1041230241341
111653843a623
127ba7b11451
133b70c04813
141dd1b30229
1511149e7c11
hex999838e3d

41230241341 has 2 divisors, whose sum is σ = 41230241342. Its totient is φ = 41230241340.

The previous prime is 41230241333. The next prime is 41230241383. The reversal of 41230241341 is 14314203214.

41230241341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 41194791225 + 35450116 = 202965^2 + 5954^2 .

It is a cyclic number.

It is not a de Polignac number, because 41230241341 - 23 = 41230241333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41230241641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20615120670 + 20615120671.

It is an arithmetic number, because the mean of its divisors is an integer number (20615120671).

Almost surely, 241230241341 is an apocalyptic number.

It is an amenable number.

41230241341 is a deficient number, since it is larger than the sum of its proper divisors (1).

41230241341 is an equidigital number, since it uses as much as digits as its factorization.

41230241341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 41230241341 its reverse (14314203214), we get a palindrome (55544444555).

The spelling of 41230241341 in words is "forty-one billion, two hundred thirty million, two hundred forty-one thousand, three hundred forty-one".