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412303311313 = 478772410879
BaseRepresentation
bin1011111111111110011…
…00010100000111010001
31110102020010102100020121
411333333030110013101
523223344121430223
6513224242510241
741534155215205
oct5777714240721
91412203370217
10412303311313
1114994751a283
1267aa7665381
132cb5958cbca
1415d541b6b05
15aad1ace15d
hex5fff3141d1

412303311313 has 4 divisors (see below), whose sum is σ = 421075722240. Its totient is φ = 403530900388.

The previous prime is 412303311281. The next prime is 412303311317. The reversal of 412303311313 is 313113303214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 412303311313 - 25 = 412303311281 is a prime.

It is not an unprimeable number, because it can be changed into a prime (412303311317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4386205393 + ... + 4386205486.

It is an arithmetic number, because the mean of its divisors is an integer number (105268930560).

Almost surely, 2412303311313 is an apocalyptic number.

It is an amenable number.

412303311313 is a deficient number, since it is larger than the sum of its proper divisors (8772410927).

412303311313 is an equidigital number, since it uses as much as digits as its factorization.

412303311313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8772410926.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 412303311313 its reverse (313113303214), we get a palindrome (725416614527).

The spelling of 412303311313 in words is "four hundred twelve billion, three hundred three million, three hundred eleven thousand, three hundred thirteen".

Divisors: 1 47 8772410879 412303311313