Base | Representation |
---|---|
bin | 10010110000000100100010… |
… | …01101101001000100001111 |
3 | 12101222221110212210021101022 |
4 | 21120002101031221010033 |
5 | 20401034440303021444 |
6 | 223410405544304355 |
7 | 11454031663451546 |
oct | 1130022115510417 |
9 | 171887425707338 |
10 | 41234122313999 |
11 | 1215832509076a |
12 | 475b5481720bb |
13 | 1a014902c31c4 |
14 | a27a5672115d |
15 | 4b78da3b79ee |
hex | 25809136910f |
41234122313999 has 2 divisors, whose sum is σ = 41234122314000. Its totient is φ = 41234122313998.
The previous prime is 41234122313977. The next prime is 41234122314101. The reversal of 41234122313999 is 99931322143214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41234122313999 - 212 = 41234122309903 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 41234122313999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41234122313399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20617061156999 + 20617061157000.
It is an arithmetic number, because the mean of its divisors is an integer number (20617061157000).
Almost surely, 241234122313999 is an apocalyptic number.
41234122313999 is a deficient number, since it is larger than the sum of its proper divisors (1).
41234122313999 is an equidigital number, since it uses as much as digits as its factorization.
41234122313999 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2519424, while the sum is 53.
The spelling of 41234122313999 in words is "forty-one trillion, two hundred thirty-four billion, one hundred twenty-two million, three hundred thirteen thousand, nine hundred ninety-nine".
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