Base | Representation |
---|---|
bin | 111100000000101101111… |
… | …000101100001111000011 |
3 | 112121020121100201210121121 |
4 | 330000231320230033003 |
5 | 1020031311220041011 |
6 | 12434302224533111 |
7 | 603642016240216 |
oct | 74005570541703 |
9 | 15536540653547 |
10 | 4123938440131 |
11 | 134aa52814094 |
12 | 5672b6781197 |
13 | 23bb68c2c543 |
14 | 10385777377d |
15 | 72416ac5e71 |
hex | 3c02de2c3c3 |
4123938440131 has 2 divisors, whose sum is σ = 4123938440132. Its totient is φ = 4123938440130.
The previous prime is 4123938440129. The next prime is 4123938440179. The reversal of 4123938440131 is 1310448393214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4123938440131 - 21 = 4123938440129 is a prime.
It is a super-2 number, since 2×41239384401312 (a number of 26 digits) contains 22 as substring.
Together with 4123938440129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4123933440131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2061969220065 + 2061969220066.
It is an arithmetic number, because the mean of its divisors is an integer number (2061969220066).
Almost surely, 24123938440131 is an apocalyptic number.
4123938440131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4123938440131 is an equidigital number, since it uses as much as digits as its factorization.
4123938440131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 43.
The spelling of 4123938440131 in words is "four trillion, one hundred twenty-three billion, nine hundred thirty-eight million, four hundred forty thousand, one hundred thirty-one".
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