Base | Representation |
---|---|
bin | 1100000000001001111… |
… | …01100010101011100001 |
3 | 1110102110212112211021001 |
4 | 12000010331202223201 |
5 | 23224043411231423 |
6 | 513242021232001 |
7 | 41536442013136 |
oct | 6000475425341 |
9 | 1412425484231 |
10 | 412400102113 |
11 | 14999711967a |
12 | 67b13b62601 |
13 | 2cb7364ba7c |
14 | 15d62db058d |
15 | aada34ccad |
hex | 6004f62ae1 |
412400102113 has 2 divisors, whose sum is σ = 412400102114. Its totient is φ = 412400102112.
The previous prime is 412400102111. The next prime is 412400102117. The reversal of 412400102113 is 311201004214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 361372906449 + 51027195664 = 601143^2 + 225892^2 .
It is a cyclic number.
It is not a de Polignac number, because 412400102113 - 21 = 412400102111 is a prime.
Together with 412400102111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (412400102111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206200051056 + 206200051057.
It is an arithmetic number, because the mean of its divisors is an integer number (206200051057).
Almost surely, 2412400102113 is an apocalyptic number.
It is an amenable number.
412400102113 is a deficient number, since it is larger than the sum of its proper divisors (1).
412400102113 is an equidigital number, since it uses as much as digits as its factorization.
412400102113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 412400102113 its reverse (311201004214), we get a palindrome (723601106327).
The spelling of 412400102113 in words is "four hundred twelve billion, four hundred million, one hundred two thousand, one hundred thirteen".
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