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4124112131 is a prime number
BaseRepresentation
bin1111010111010000…
…1111010100000011
3101122102020121021202
43311310033110003
531421233042011
61521122011415
7204125242346
oct36564172403
911572217252
104124112131
111826a54537
129711a6b6b
13509558249
142b1a2045d
151920de23b
hexf5d0f503

4124112131 has 2 divisors, whose sum is σ = 4124112132. Its totient is φ = 4124112130.

The previous prime is 4124112079. The next prime is 4124112193. The reversal of 4124112131 is 1312114214.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4124112131 - 222 = 4119917827 is a prime.

It is a super-2 number, since 2×41241121312 = 34016601738122722322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4124172131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062056065 + 2062056066.

It is an arithmetic number, because the mean of its divisors is an integer number (2062056066).

Almost surely, 24124112131 is an apocalyptic number.

4124112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4124112131 is an equidigital number, since it uses as much as digits as its factorization.

4124112131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 192, while the sum is 20.

The square root of 4124112131 is about 64219.2504705559. The cubic root of 4124112131 is about 1603.6520912747.

Adding to 4124112131 its reverse (1312114214), we get a palindrome (5436226345).

The spelling of 4124112131 in words is "four billion, one hundred twenty-four million, one hundred twelve thousand, one hundred thirty-one".