Base | Representation |
---|---|
bin | 10010110000010001100111… |
… | …01111011010101110100111 |
3 | 12102000121121020102010202021 |
4 | 21120020303233122232213 |
5 | 20401143330333410310 |
6 | 223413530420324011 |
7 | 11454400665255115 |
oct | 1130106357325647 |
9 | 172017536363667 |
10 | 41241144044455 |
11 | 121602a8727793 |
12 | 4760987843607 |
13 | 1a0203bc670b4 |
14 | a281210d6ab5 |
15 | 4b7b9ba755da |
hex | 258233bdaba7 |
41241144044455 has 32 divisors (see below), whose sum is σ = 52756373150208. Its totient is φ = 30894057331200.
The previous prime is 41241144044341. The next prime is 41241144044467. The reversal of 41241144044455 is 55444044114214.
It is not a de Polignac number, because 41241144044455 - 233 = 41232554109863 is a prime.
It is a super-2 number, since 2×412411440444552 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18826972 + ... + 20903041.
It is an arithmetic number, because the mean of its divisors is an integer number (1648636660944).
Almost surely, 241241144044455 is an apocalyptic number.
41241144044455 is a deficient number, since it is larger than the sum of its proper divisors (11515229105753).
41241144044455 is a wasteful number, since it uses less digits than its factorization.
41241144044455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39730267.
The product of its (nonzero) digits is 819200, while the sum is 43.
Adding to 41241144044455 its reverse (55444044114214), we get a palindrome (96685188158669).
The spelling of 41241144044455 in words is "forty-one trillion, two hundred forty-one billion, one hundred forty-four million, forty-four thousand, four hundred fifty-five".
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