4124123314141 has 2 divisors, whose sum is σ = 4124123314142. Its totient is φ = 4124123314140.

The previous prime is 4124123314097. The next prime is 4124123314163. The reversal of 4124123314141 is 1414133214214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2570423388516 + 1553699925625 = 1603254^2 + 1246475^2 .

It is a cyclic number.

It is not a de Polignac number, because 4124123314141 - 2¹¹ = 4124123312093 is a prime.

It is a super-2 number, since 2×4124123314141² (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4124123344141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062061657070 + 2062061657071.

It is an arithmetic number, because the mean of its divisors is an integer number (2062061657071).

Almost surely, 2^{4124123314141} is an apocalyptic number.

It is an amenable number.

4124123314141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4124123314141 is an equidigital number, since it uses as much as digits as its factorization.

4124123314141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9216, while the sum is 31.

Adding to 4124123314141 its reverse (1414133214214), we get a palindrome (5538256528355).

The spelling of 4124123314141 in words is "four trillion, one hundred twenty-four billion, one hundred twenty-three million, three hundred fourteen thousand, one hundred forty-one".