Base | Representation |
---|---|
bin | 100110011010001011… |
… | …000111100010110011 |
3 | 10221110011210200122012 |
4 | 212122023013202303 |
5 | 1133430233431121 |
6 | 30540200233135 |
7 | 2656666235336 |
oct | 463213074263 |
9 | 127404720565 |
10 | 41241311411 |
11 | 16543710743 |
12 | 7bab76b7ab |
13 | 3b732ac461 |
14 | 1dd33b261d |
15 | 1115982c5b |
hex | 99a2c78b3 |
41241311411 has 4 divisors (see below), whose sum is σ = 41822175024. Its totient is φ = 40660447800.
The previous prime is 41241311399. The next prime is 41241311471. The reversal of 41241311411 is 11411314214.
41241311411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11411314214 = 2 ⋅5705657107.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41241311411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41241311471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290431700 + ... + 290431841.
It is an arithmetic number, because the mean of its divisors is an integer number (10455543756).
Almost surely, 241241311411 is an apocalyptic number.
41241311411 is a deficient number, since it is larger than the sum of its proper divisors (580863613).
41241311411 is an equidigital number, since it uses as much as digits as its factorization.
41241311411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 580863612.
The product of its digits is 384, while the sum is 23.
Adding to 41241311411 its reverse (11411314214), we get a palindrome (52652625625).
The spelling of 41241311411 in words is "forty-one billion, two hundred forty-one million, three hundred eleven thousand, four hundred eleven".
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