Base | Representation |
---|---|
bin | 1100000000001100010… |
… | …01111010001100111011 |
3 | 1110102112021012220120020 |
4 | 12000012021322030323 |
5 | 23224114022341103 |
6 | 513244014301523 |
7 | 41540104122333 |
oct | 6000611721473 |
9 | 1412467186506 |
10 | 412420121403 |
11 | 1499a7452444 |
12 | 67b1a7b78a3 |
13 | 2cb7783abc4 |
14 | 15d659020c3 |
15 | aadbea4753 |
hex | 600627a33b |
412420121403 has 4 divisors (see below), whose sum is σ = 549893495208. Its totient is φ = 274946747600.
The previous prime is 412420121381. The next prime is 412420121411. The reversal of 412420121403 is 304121024214.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 412420121403 - 25 = 412420121371 is a prime.
It is not an unprimeable number, because it can be changed into a prime (412420121203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68736686898 + ... + 68736686903.
It is an arithmetic number, because the mean of its divisors is an integer number (137473373802).
Almost surely, 2412420121403 is an apocalyptic number.
412420121403 is a deficient number, since it is larger than the sum of its proper divisors (137473373805).
412420121403 is a wasteful number, since it uses less digits than its factorization.
412420121403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 137473373804.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 412420121403 its reverse (304121024214), we get a palindrome (716541145617).
The spelling of 412420121403 in words is "four hundred twelve billion, four hundred twenty million, one hundred twenty-one thousand, four hundred three".
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