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41243112433 is a prime number
BaseRepresentation
bin100110011010010001…
…111111001111110001
310221110022012012011201
4212122101333033301
51133431214044213
630540303011201
72660020446205
oct463221771761
9127408165151
1041243112433
1116544730896
127bb0299b01
133b73790153
141dd3720b05
151115bdb6dd
hex99a47f3f1

41243112433 has 2 divisors, whose sum is σ = 41243112434. Its totient is φ = 41243112432.

The previous prime is 41243112367. The next prime is 41243112487. The reversal of 41243112433 is 33421134214.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40150942129 + 1092170304 = 200377^2 + 33048^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41243112433 is a prime.

It is a super-2 number, since 2×412431124332 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (41243112733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20621556216 + 20621556217.

It is an arithmetic number, because the mean of its divisors is an integer number (20621556217).

Almost surely, 241243112433 is an apocalyptic number.

It is an amenable number.

41243112433 is a deficient number, since it is larger than the sum of its proper divisors (1).

41243112433 is an equidigital number, since it uses as much as digits as its factorization.

41243112433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 28.

Adding to 41243112433 its reverse (33421134214), we get a palindrome (74664246647).

The spelling of 41243112433 in words is "forty-one billion, two hundred forty-three million, one hundred twelve thousand, four hundred thirty-three".