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412443113434403 is a prime number
BaseRepresentation
bin101110111000111010110010…
…1010001000010110100100011
32000002100011202201102222111212
41131301311211101002310203
5413024431444014400103
64021105430043500335
7152606013561000032
oct13561654521026443
92002304681388455
10412443113434403
1110a465162189217
123a3122a42276ab
131491a2ac67b0ac
1473bc4d328a719
1532a38d292d7d8
hex1771d65442d23

412443113434403 has 2 divisors, whose sum is σ = 412443113434404. Its totient is φ = 412443113434402.

The previous prime is 412443113434301. The next prime is 412443113434507. The reversal of 412443113434403 is 304434311344214.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 412443113434403 - 28 = 412443113434147 is a prime.

It is not a weakly prime, because it can be changed into another prime (412443113431403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206221556717201 + 206221556717202.

It is an arithmetic number, because the mean of its divisors is an integer number (206221556717202).

Almost surely, 2412443113434403 is an apocalyptic number.

412443113434403 is a deficient number, since it is larger than the sum of its proper divisors (1).

412443113434403 is an equidigital number, since it uses as much as digits as its factorization.

412443113434403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 663552, while the sum is 41.

Adding to 412443113434403 its reverse (304434311344214), we get a palindrome (716877424778617).

The spelling of 412443113434403 in words is "four hundred twelve trillion, four hundred forty-three billion, one hundred thirteen million, four hundred thirty-four thousand, four hundred three".