4125253104041 has 4 divisors (see below), whose sum is σ = 4174954948752. Its totient is φ = 4075551259332.

The previous prime is 4125253104023. The next prime is 4125253104043. The reversal of 4125253104041 is 1404013525214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4125253104041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4125253103989 and 4125253104007.

It is not an unprimeable number, because it can be changed into a prime (4125253104043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24850922231 + ... + 24850922396.

It is an arithmetic number, because the mean of its divisors is an integer number (1043738737188).

Almost surely, 2^{4125253104041} is an apocalyptic number.

It is an amenable number.

4125253104041 is a deficient number, since it is larger than the sum of its proper divisors (49701844711).

4125253104041 is an equidigital number, since it uses as much as digits as its factorization.

4125253104041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49701844710.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 4125253104041 its reverse (1404013525214), we get a palindrome (5529266629255).

The spelling of 4125253104041 in words is "four trillion, one hundred twenty-five billion, two hundred fifty-three million, one hundred four thousand, forty-one".