Base | Representation |
---|---|
bin | 111100000010000110010… |
… | …001000011110011000111 |
3 | 112121101102200211222110202 |
4 | 330002012101003303013 |
5 | 1020042330313114421 |
6 | 12435105314041115 |
7 | 604023532546526 |
oct | 74020621036307 |
9 | 15541380758422 |
10 | 4125421223111 |
11 | 1350643804971 |
12 | 56764b27919b |
13 | 23c0441a4016 |
14 | 1039586744bd |
15 | 724a1d6e10b |
hex | 3c086443cc7 |
4125421223111 has 4 divisors (see below), whose sum is σ = 4125434534424. Its totient is φ = 4125407911800.
The previous prime is 4125421223089. The next prime is 4125421223113. The reversal of 4125421223111 is 1113221245214.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4125421223111 - 238 = 3850543316167 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4125421223113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6179420 + ... + 6814401.
It is an arithmetic number, because the mean of its divisors is an integer number (1031358633606).
Almost surely, 24125421223111 is an apocalyptic number.
4125421223111 is a deficient number, since it is larger than the sum of its proper divisors (13311313).
4125421223111 is a wasteful number, since it uses less digits than its factorization.
4125421223111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13311312.
The product of its digits is 3840, while the sum is 29.
Adding to 4125421223111 its reverse (1113221245214), we get a palindrome (5238642468325).
The spelling of 4125421223111 in words is "four trillion, one hundred twenty-five billion, four hundred twenty-one million, two hundred twenty-three thousand, one hundred eleven".
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