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4130020112019 = 311321121603513
BaseRepresentation
bin111100000110011000011…
…000011011011010010011
3112121211022012110202001120
4330012120120123122103
51020131240122041034
612441145520133323
7604245514504104
oct74063030333223
915554265422046
104130020112019
1113525937581aa
12568513467243
1323c5c7bc2669
14103c733623ab
1572670992c49
hex3c19861b693

4130020112019 has 8 divisors (see below), whose sum is σ = 5507179942032. Its totient is φ = 2753103511680.

The previous prime is 4130020111961. The next prime is 4130020112047. The reversal of 4130020112019 is 9102110200314.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 4130020112019 - 216 = 4130020046483 is a prime.

It is a super-2 number, since 2×41300201120192 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4130020112019.

It is not an unprimeable number, because it can be changed into a prime (4130020112059) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60767794 + ... + 60835719.

It is an arithmetic number, because the mean of its divisors is an integer number (688397492754).

Almost surely, 24130020112019 is an apocalyptic number.

4130020112019 is a deficient number, since it is larger than the sum of its proper divisors (1377159830013).

4130020112019 is a wasteful number, since it uses less digits than its factorization.

4130020112019 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121614837.

The product of its (nonzero) digits is 432, while the sum is 24.

The spelling of 4130020112019 in words is "four trillion, one hundred thirty billion, twenty million, one hundred twelve thousand, nineteen".

Divisors: 1 3 11321 33963 121603513 364810539 1376673370673 4130020112019