Base | Representation |
---|---|
bin | 111100000110011000011… |
… | …000011011011010010100 |
3 | 112121211022012110202001121 |
4 | 330012120120123122110 |
5 | 1020131240122041040 |
6 | 12441145520133324 |
7 | 604245514504105 |
oct | 74063030333224 |
9 | 15554265422047 |
10 | 4130020112020 |
11 | 1352593758200 |
12 | 568513467244 |
13 | 23c5c7bc266a |
14 | 103c733623ac |
15 | 72670992c4a |
hex | 3c19861b694 |
4130020112020 has 72 divisors (see below), whose sum is σ = 10034925012000. Its totient is φ = 1422782032320.
The previous prime is 4130020111961. The next prime is 4130020112047. The reversal of 4130020112020 is 202110200314.
It is a super-2 number, since 2×41300201120202 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4130020111985 and 4130020112003.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 44865070 + ... + 44957029.
It is an arithmetic number, because the mean of its divisors is an integer number (139373958500).
Almost surely, 24130020112020 is an apocalyptic number.
It is an amenable number.
4130020112020 is an abundant number, since it is smaller than the sum of its proper divisors (5904904899980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4130020112020 is a wasteful number, since it uses less digits than its factorization.
4130020112020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89822149 (or 89822136 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 4130020112020 its reverse (202110200314), we get a palindrome (4332130312334).
The spelling of 4130020112020 in words is "four trillion, one hundred thirty billion, twenty million, one hundred twelve thousand, twenty".
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