Base | Representation |
---|---|
bin | 100110011101101100… |
… | …101001000010011001 |
3 | 10221121022001021110122 |
4 | 212131230221002121 |
5 | 1134040402243001 |
6 | 30550111323025 |
7 | 2661314604554 |
oct | 463554510231 |
9 | 127538037418 |
10 | 41300431001 |
11 | 16574020105 |
12 | 8007520475 |
13 | 3b8260b76b |
14 | 1ddb1a169b |
15 | 111ac5eb1b |
hex | 99db29099 |
41300431001 has 4 divisors (see below), whose sum is σ = 41301269604. Its totient is φ = 41299592400.
The previous prime is 41300430979. The next prime is 41300431009. The reversal of 41300431001 is 10013400314.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 24736998400 + 16563432601 = 157280^2 + 128699^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41300431001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41300431009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 340490 + ... + 445571.
It is an arithmetic number, because the mean of its divisors is an integer number (10325317401).
Almost surely, 241300431001 is an apocalyptic number.
It is an amenable number.
41300431001 is a deficient number, since it is larger than the sum of its proper divisors (838603).
41300431001 is an equidigital number, since it uses as much as digits as its factorization.
41300431001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 838602.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 41300431001 its reverse (10013400314), we get a palindrome (51313831315).
The spelling of 41300431001 in words is "forty-one billion, three hundred million, four hundred thirty-one thousand, one".
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