Base | Representation |
---|---|
bin | 111100000110100011001… |
… | …110110001011001010001 |
3 | 112121211202212222012210022 |
4 | 330012203032301121101 |
5 | 1020132123221130001 |
6 | 12441215541313225 |
7 | 604253154565553 |
oct | 74064316613121 |
9 | 15554685865708 |
10 | 4130202130001 |
11 | 1352677478a92 |
12 | 568564405815 |
13 | 23c626821bcc |
14 | 103c8d5c34d3 |
15 | 7268194911b |
hex | 3c1a33b1651 |
4130202130001 has 2 divisors, whose sum is σ = 4130202130002. Its totient is φ = 4130202130000.
The previous prime is 4130202129943. The next prime is 4130202130013. The reversal of 4130202130001 is 1000312020314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3066704942401 + 1063497187600 = 1751201^2 + 1031260^2 .
It is a cyclic number.
It is not a de Polignac number, because 4130202130001 - 234 = 4113022260817 is a prime.
It is not a weakly prime, because it can be changed into another prime (4130202130051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065101065000 + 2065101065001.
It is an arithmetic number, because the mean of its divisors is an integer number (2065101065001).
Almost surely, 24130202130001 is an apocalyptic number.
It is an amenable number.
4130202130001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130202130001 is an equidigital number, since it uses as much as digits as its factorization.
4130202130001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 4130202130001 its reverse (1000312020314), we get a palindrome (5130514150315).
The spelling of 4130202130001 in words is "four trillion, one hundred thirty billion, two hundred two million, one hundred thirty thousand, one".
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