413030230444541 has 4 divisors (see below), whose sum is σ = 414758390404800. Its totient is φ = 411302070484284.

The previous prime is 413030230444501. The next prime is 413030230444549. The reversal of 413030230444541 is 145444032030314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 413030230444541 - 2¹⁰ = 413030230443517 is a prime.

It is a super-2 number, since 2×413030230444541² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 413030230444495 and 413030230444504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (413030230444549) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 864079979771 + ... + 864079980248.

It is an arithmetic number, because the mean of its divisors is an integer number (103689597601200).

Almost surely, 2^{413030230444541} is an apocalyptic number.

It is an amenable number.

413030230444541 is a deficient number, since it is larger than the sum of its proper divisors (1728159960259).

413030230444541 is a wasteful number, since it uses less digits than its factorization.

413030230444541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1728159960258.

The product of its (nonzero) digits is 276480, while the sum is 38.

Adding to 413030230444541 its reverse (145444032030314), we get a palindrome (558474262474855).

The spelling of 413030230444541 in words is "four hundred thirteen trillion, thirty billion, two hundred thirty million, four hundred forty-four thousand, five hundred forty-one".