Base | Representation |
---|---|
bin | 101110111101010001010000… |
… | …0010010011101010111001111 |
3 | 2000011110100021201102001011112 |
4 | 1131322202200102131113033 |
5 | 413114231140123141101 |
6 | 4022244244055242235 |
7 | 153000143414630321 |
oct | 13572424022352717 |
9 | 2004410251361145 |
10 | 413041104115151 |
11 | 10a67582634a496 |
12 | 3a3aa17207937b |
13 | 149617bbc4a4a5 |
14 | 73dd42072b611 |
15 | 32b42311976bb |
hex | 177a8a049d5cf |
413041104115151 has 2 divisors, whose sum is σ = 413041104115152. Its totient is φ = 413041104115150.
The previous prime is 413041104115127. The next prime is 413041104115169. The reversal of 413041104115151 is 151511401140314.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-413041104115151 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413041104115351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206520552057575 + 206520552057576.
It is an arithmetic number, because the mean of its divisors is an integer number (206520552057576).
Almost surely, 2413041104115151 is an apocalyptic number.
413041104115151 is a deficient number, since it is larger than the sum of its proper divisors (1).
413041104115151 is an equidigital number, since it uses as much as digits as its factorization.
413041104115151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 32.
Adding to 413041104115151 its reverse (151511401140314), we get a palindrome (564552505255465).
The spelling of 413041104115151 in words is "four hundred thirteen trillion, forty-one billion, one hundred four million, one hundred fifteen thousand, one hundred fifty-one".
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