Base | Representation |
---|---|
bin | 1100000001010110011… |
… | …10101101000110000111 |
3 | 1110111010121122111101211 |
4 | 12000223032231012013 |
5 | 23231402241313211 |
6 | 513425434232251 |
7 | 41561366136322 |
oct | 6005316550607 |
9 | 1414117574354 |
10 | 413042135431 |
11 | 14a196576822 |
12 | 68072b85687 |
13 | 2cc46673843 |
14 | 15dc43797b9 |
15 | ab268bee21 |
hex | 602b3ad187 |
413042135431 has 2 divisors, whose sum is σ = 413042135432. Its totient is φ = 413042135430.
The previous prime is 413042135423. The next prime is 413042135501. The reversal of 413042135431 is 134531240314.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 413042135431 - 23 = 413042135423 is a prime.
It is a super-2 number, since 2×4130421354312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 413042135393 and 413042135402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413042135731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206521067715 + 206521067716.
It is an arithmetic number, because the mean of its divisors is an integer number (206521067716).
Almost surely, 2413042135431 is an apocalyptic number.
413042135431 is a deficient number, since it is larger than the sum of its proper divisors (1).
413042135431 is an equidigital number, since it uses as much as digits as its factorization.
413042135431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 413042135431 its reverse (134531240314), we get a palindrome (547573375745).
The spelling of 413042135431 in words is "four hundred thirteen billion, forty-two million, one hundred thirty-five thousand, four hundred thirty-one".
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