Base | Representation |
---|---|
bin | 100110011101111110… |
… | …000101110010111001 |
3 | 10221121121122200010221 |
4 | 212131332011302321 |
5 | 1134043040131431 |
6 | 30550353340041 |
7 | 2661401515543 |
oct | 463576056271 |
9 | 127547580127 |
10 | 41305005241 |
11 | 16576664875 |
12 | 8008b67621 |
13 | 3b83550806 |
14 | 1ddba32693 |
15 | 111b365111 |
hex | 99df85cb9 |
41305005241 has 4 divisors (see below), whose sum is σ = 42421356772. Its totient is φ = 40188653712.
The previous prime is 41305005233. The next prime is 41305005251. The reversal of 41305005241 is 14250050314.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 35675654400 + 5629350841 = 188880^2 + 75029^2 .
It is a cyclic number.
It is not a de Polignac number, because 41305005241 - 23 = 41305005233 is a prime.
It is a super-2 number, since 2×413050052412 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (41305005251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 558175710 + ... + 558175783.
It is an arithmetic number, because the mean of its divisors is an integer number (10605339193).
Almost surely, 241305005241 is an apocalyptic number.
It is an amenable number.
41305005241 is a deficient number, since it is larger than the sum of its proper divisors (1116351531).
41305005241 is a wasteful number, since it uses less digits than its factorization.
41305005241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1116351530.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 41305005241 its reverse (14250050314), we get a palindrome (55555055555).
The spelling of 41305005241 in words is "forty-one billion, three hundred five million, five thousand, two hundred forty-one".
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