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4131042401323 is a prime number
BaseRepresentation
bin111100000111010101010…
…100001001110000101011
3112121220221110002102100101
4330013111110021300223
51020140333323320243
612441435155250231
7604313040020305
oct74072524116053
915556843072311
104131042401323
111352a688152a2
125687598a9977
1323c72b934c86
14103d2d032975
15726d05c854d
hex3c1d5509c2b

4131042401323 has 2 divisors, whose sum is σ = 4131042401324. Its totient is φ = 4131042401322.

The previous prime is 4131042401287. The next prime is 4131042401329. The reversal of 4131042401323 is 3231042401314.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4131042401323 is a prime.

It is a super-2 number, since 2×41310424013232 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4131042401291 and 4131042401300.

It is not a weakly prime, because it can be changed into another prime (4131042401329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065521200661 + 2065521200662.

It is an arithmetic number, because the mean of its divisors is an integer number (2065521200662).

Almost surely, 24131042401323 is an apocalyptic number.

4131042401323 is a deficient number, since it is larger than the sum of its proper divisors (1).

4131042401323 is an equidigital number, since it uses as much as digits as its factorization.

4131042401323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 4131042401323 its reverse (3231042401314), we get a palindrome (7362084802637).

Subtracting from 4131042401323 its reverse (3231042401314), we obtain a palindrome (900000000009).

The spelling of 4131042401323 in words is "four trillion, one hundred thirty-one billion, forty-two million, four hundred one thousand, three hundred twenty-three".