Base | Representation |
---|---|
bin | 101110111101101111000011… |
… | …1101001110101111001001111 |
3 | 2000011200110111202210100222211 |
4 | 1131323132013221311321033 |
5 | 413121303234010331413 |
6 | 4022333511533451251 |
7 | 153004600602134365 |
oct | 13573360751657117 |
9 | 2004613452710884 |
10 | 413105115323983 |
11 | 10a69a993a77075 |
12 | 3a3ba657340b27 |
13 | 14967850721c14 |
14 | 7402573c11635 |
15 | 32b5c2ab3683d |
hex | 177b787a75e4f |
413105115323983 has 2 divisors, whose sum is σ = 413105115323984. Its totient is φ = 413105115323982.
The previous prime is 413105115323969. The next prime is 413105115324091. The reversal of 413105115323983 is 389323511501314.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 413105115323983 - 221 = 413105113226831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413105115323933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206552557661991 + 206552557661992.
It is an arithmetic number, because the mean of its divisors is an integer number (206552557661992).
Almost surely, 2413105115323983 is an apocalyptic number.
413105115323983 is a deficient number, since it is larger than the sum of its proper divisors (1).
413105115323983 is an equidigital number, since it uses as much as digits as its factorization.
413105115323983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1166400, while the sum is 49.
The spelling of 413105115323983 in words is "four hundred thirteen trillion, one hundred five billion, one hundred fifteen million, three hundred twenty-three thousand, nine hundred eighty-three".
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