Base | Representation |
---|---|
bin | 101110111101101111000011… |
… | …1101001110101111001100001 |
3 | 2000011200110111202210101000111 |
4 | 1131323132013221311321201 |
5 | 413121303234010332001 |
6 | 4022333511533451321 |
7 | 153004600602134422 |
oct | 13573360751657141 |
9 | 2004613452711014 |
10 | 413105115324001 |
11 | 10a69a993a77091 |
12 | 3a3ba657340b41 |
13 | 14967850721c29 |
14 | 7402573c11649 |
15 | 32b5c2ab36851 |
hex | 177b787a75e61 |
413105115324001 has 16 divisors (see below), whose sum is σ = 413575241564160. Its totient is φ = 412635338191440.
The previous prime is 413105115323983. The next prime is 413105115324091. The reversal of 413105115324001 is 100423511501314.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 413105115324001 - 25 = 413105115323969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (413105115324091) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38654913280 + ... + 38654923966.
It is an arithmetic number, because the mean of its divisors is an integer number (25848452597760).
Almost surely, 2413105115324001 is an apocalyptic number.
It is an amenable number.
413105115324001 is a deficient number, since it is larger than the sum of its proper divisors (470126240159).
413105115324001 is a wasteful number, since it uses less digits than its factorization.
413105115324001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23244.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 413105115324001 its reverse (100423511501314), we get a palindrome (513528626825315).
The spelling of 413105115324001 in words is "four hundred thirteen trillion, one hundred five billion, one hundred fifteen million, three hundred twenty-four thousand, one".
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