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413110421413 is a prime number
BaseRepresentation
bin1100000001011110100…
…11001100011110100101
31110111022101010210011021
412000233103030132211
523232022231441123
6513440314011141
741563155433654
oct6005723143645
91414271123137
10413110421413
1114a221077018
1268091a16ab1
132cc57862151
1415dcd47319b
15ab2c8acc5d
hex602f4cc7a5

413110421413 has 2 divisors, whose sum is σ = 413110421414. Its totient is φ = 413110421412.

The previous prime is 413110421407. The next prime is 413110421461. The reversal of 413110421413 is 314124011314.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 357247680804 + 55862740609 = 597702^2 + 236353^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-413110421413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (413110421483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206555210706 + 206555210707.

It is an arithmetic number, because the mean of its divisors is an integer number (206555210707).

Almost surely, 2413110421413 is an apocalyptic number.

It is an amenable number.

413110421413 is a deficient number, since it is larger than the sum of its proper divisors (1).

413110421413 is an equidigital number, since it uses as much as digits as its factorization.

413110421413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 413110421413 its reverse (314124011314), we get a palindrome (727234432727).

The spelling of 413110421413 in words is "four hundred thirteen billion, one hundred ten million, four hundred twenty-one thousand, four hundred thirteen".