Base | Representation |
---|---|
bin | 1100000001011110111… |
… | …01110101100111001101 |
3 | 1110111022120101112012221 |
4 | 12000233131311213031 |
5 | 23232023440230331 |
6 | 513440453455341 |
7 | 41563221233605 |
oct | 6005735654715 |
9 | 1414276345187 |
10 | 413113211341 |
11 | 14a222702146 |
12 | 68092941551 |
13 | 2cc582cacac |
14 | 15dcd99bc05 |
15 | ab2cc5e711 |
hex | 602f7759cd |
413113211341 has 2 divisors, whose sum is σ = 413113211342. Its totient is φ = 413113211340.
The previous prime is 413113211327. The next prime is 413113211353. The reversal of 413113211341 is 143112311314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 387338193225 + 25775018116 = 622365^2 + 160546^2 .
It is a cyclic number.
It is not a de Polignac number, because 413113211341 - 215 = 413113178573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413113211041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206556605670 + 206556605671.
It is an arithmetic number, because the mean of its divisors is an integer number (206556605671).
Almost surely, 2413113211341 is an apocalyptic number.
It is an amenable number.
413113211341 is a deficient number, since it is larger than the sum of its proper divisors (1).
413113211341 is an equidigital number, since it uses as much as digits as its factorization.
413113211341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864, while the sum is 25.
Adding to 413113211341 its reverse (143112311314), we get a palindrome (556225522655).
The spelling of 413113211341 in words is "four hundred thirteen billion, one hundred thirteen million, two hundred eleven thousand, three hundred forty-one".
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