Base | Representation |
---|---|
bin | 111100000111100101011… |
… | …001011110000000110011 |
3 | 112121221122020211011022210 |
4 | 330013211121132000303 |
5 | 1020141411412333301 |
6 | 12441522034503203 |
7 | 604322524360200 |
oct | 74074531360063 |
9 | 15557566734283 |
10 | 4131312230451 |
11 | 135309706197a |
12 | 568814134b03 |
13 | 23c7727cb093 |
14 | 103d56bd0ca7 |
15 | 726e9127ad6 |
hex | 3c1e565e033 |
4131312230451 has 24 divisors (see below), whose sum is σ = 6528650529744. Its totient is φ = 2316207391680.
The previous prime is 4131312230411. The next prime is 4131312230459. The reversal of 4131312230451 is 1540322131314.
4131312230451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4131312230451 - 210 = 4131312229427 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4131312230459) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 265125840 + ... + 265141421.
It is an arithmetic number, because the mean of its divisors is an integer number (272027105406).
Almost surely, 24131312230451 is an apocalyptic number.
4131312230451 is a deficient number, since it is larger than the sum of its proper divisors (2397338299293).
4131312230451 is a wasteful number, since it uses less digits than its factorization.
4131312230451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 530267331 (or 530267324 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 4131312230451 its reverse (1540322131314), we get a palindrome (5671634361765).
The spelling of 4131312230451 in words is "four trillion, one hundred thirty-one billion, three hundred twelve million, two hundred thirty thousand, four hundred fifty-one".
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