Base | Representation |
---|---|
bin | 101110111110000001101001… |
… | …0111100000111001110011111 |
3 | 2000011211021112201011000200221 |
4 | 1131330003102330013032133 |
5 | 413122432011434013211 |
6 | 4022404112534302211 |
7 | 153010513030542466 |
oct | 13574032274071637 |
9 | 2004737481130627 |
10 | 413145033110431 |
11 | 10a705908581926 |
12 | 3a4063377b7967 |
13 | 1496b54274a6bb |
14 | 740447d4db9dd |
15 | 32b6cb52cdc71 |
hex | 177c0d2f0739f |
413145033110431 has 2 divisors, whose sum is σ = 413145033110432. Its totient is φ = 413145033110430.
The previous prime is 413145033110309. The next prime is 413145033110521. The reversal of 413145033110431 is 134011330541314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 413145033110431 - 227 = 413144898892703 is a prime.
It is a super-2 number, since 2×4131450331104312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413145033119431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206572516555215 + 206572516555216.
It is an arithmetic number, because the mean of its divisors is an integer number (206572516555216).
Almost surely, 2413145033110431 is an apocalyptic number.
413145033110431 is a deficient number, since it is larger than the sum of its proper divisors (1).
413145033110431 is an equidigital number, since it uses as much as digits as its factorization.
413145033110431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 413145033110431 its reverse (134011330541314), we get a palindrome (547156363651745).
The spelling of 413145033110431 in words is "four hundred thirteen trillion, one hundred forty-five billion, thirty-three million, one hundred ten thousand, four hundred thirty-one".
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