Base | Representation |
---|---|
bin | 101110111110000001101001… |
… | …0111100001000000100101111 |
3 | 2000011211021112201011012110112 |
4 | 1131330003102330020010233 |
5 | 413122432011434121103 |
6 | 4022404112534330235 |
7 | 153010513030555556 |
oct | 13574032274100457 |
9 | 2004737481135415 |
10 | 413145033113903 |
11 | 10a7059085844a2 |
12 | 3a4063377b997b |
13 | 1496b54274c15c |
14 | 740447d4dcd9d |
15 | 32b6cb52cecd8 |
hex | 177c0d2f0812f |
413145033113903 has 2 divisors, whose sum is σ = 413145033113904. Its totient is φ = 413145033113902.
The previous prime is 413145033113819. The next prime is 413145033113927. The reversal of 413145033113903 is 309311330541314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 413145033113903 - 214 = 413145033097519 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413145033113003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206572516556951 + 206572516556952.
It is an arithmetic number, because the mean of its divisors is an integer number (206572516556952).
Almost surely, 2413145033113903 is an apocalyptic number.
413145033113903 is a deficient number, since it is larger than the sum of its proper divisors (1).
413145033113903 is an equidigital number, since it uses as much as digits as its factorization.
413145033113903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 174960, while the sum is 41.
The spelling of 413145033113903 in words is "four hundred thirteen trillion, one hundred forty-five billion, thirty-three million, one hundred thirteen thousand, nine hundred three".
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