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413210233 = 1921747907
BaseRepresentation
bin11000101000010…
…001011001111001
31001210112020212201
4120220101121321
51321240211413
6105000310201
713145141362
oct3050213171
91053466781
10413210233
111a2278a67
12b6472361
13677b83c7
143cc42b69
15264229dd
hex18a11679

413210233 has 4 divisors (see below), whose sum is σ = 434958160. Its totient is φ = 391462308.

The previous prime is 413210209. The next prime is 413210243. The reversal of 413210233 is 332012314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 413210233 - 25 = 413210201 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 21747907 = 413210233 / (4 + 1 + 3 + 2 + 1 + 0 + 2 + 3 + 3).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 413210233.

It is not an unprimeable number, because it can be changed into a prime (413210243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10873935 + ... + 10873972.

It is an arithmetic number, because the mean of its divisors is an integer number (108739540).

Almost surely, 2413210233 is an apocalyptic number.

It is an amenable number.

413210233 is a deficient number, since it is larger than the sum of its proper divisors (21747927).

413210233 is a wasteful number, since it uses less digits than its factorization.

413210233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21747926.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 413210233 is about 20327.5732196443. The cubic root of 413210233 is about 744.8297633641.

Adding to 413210233 its reverse (332012314), we get a palindrome (745222547).

It can be divided in two parts, 4132 and 10233, that added together give a triangular number (14365 = T169).

The spelling of 413210233 in words is "four hundred thirteen million, two hundred ten thousand, two hundred thirty-three".

Divisors: 1 19 21747907 413210233