Base | Representation |
---|---|
bin | 10010110010100110100110… |
… | …10110100110010110011111 |
3 | 12102022021001200112221121112 |
4 | 21121103103112212112133 |
5 | 20404001134103214401 |
6 | 223514355441052235 |
7 | 11463232103615423 |
oct | 1131232326462637 |
9 | 172267050487545 |
10 | 41321131304351 |
11 | 12191214421a58 |
12 | 477438b32707b |
13 | 1a0974855b092 |
14 | a2bd4c2b6b83 |
15 | 4b9ccdd793bb |
hex | 2594d35a659f |
41321131304351 has 2 divisors, whose sum is σ = 41321131304352. Its totient is φ = 41321131304350.
The previous prime is 41321131304261. The next prime is 41321131304357. The reversal of 41321131304351 is 15340313112314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41321131304351 - 222 = 41321127110047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41321131304357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20660565652175 + 20660565652176.
It is an arithmetic number, because the mean of its divisors is an integer number (20660565652176).
Almost surely, 241321131304351 is an apocalyptic number.
41321131304351 is a deficient number, since it is larger than the sum of its proper divisors (1).
41321131304351 is an equidigital number, since it uses as much as digits as its factorization.
41321131304351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 32.
Adding to 41321131304351 its reverse (15340313112314), we get a palindrome (56661444416665).
The spelling of 41321131304351 in words is "forty-one trillion, three hundred twenty-one billion, one hundred thirty-one million, three hundred four thousand, three hundred fifty-one".
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