413220240241241 has 2 divisors, whose sum is σ = 413220240241242. Its totient is φ = 413220240241240.

The previous prime is 413220240241223. The next prime is 413220240241243. The reversal of 413220240241241 is 142142042022314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 231733000482841 + 181487239758400 = 15222779^2 + 13471720^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-413220240241241 is a prime.

Together with 413220240241243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 413220240241198 and 413220240241207.

It is not a weakly prime, because it can be changed into another prime (413220240241243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206610120120620 + 206610120120621.

It is an arithmetic number, because the mean of its divisors is an integer number (206610120120621).

Almost surely, 2^{413220240241241} is an apocalyptic number.

It is an amenable number.

413220240241241 is a deficient number, since it is larger than the sum of its proper divisors (1).

413220240241241 is an equidigital number, since it uses as much as digits as its factorization.

413220240241241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24576, while the sum is 32.

Adding to 413220240241241 its reverse (142142042022314), we get a palindrome (555362282263555).

The spelling of 413220240241241 in words is "four hundred thirteen trillion, two hundred twenty billion, two hundred forty million, two hundred forty-one thousand, two hundred forty-one".