Base | Representation |
---|---|
bin | 100110011111000100… |
… | …010011011011001111 |
3 | 10221122220021210022022 |
4 | 212133010103123033 |
5 | 1134112243124101 |
6 | 30552252040355 |
7 | 2662014125231 |
oct | 463704233317 |
9 | 127586253268 |
10 | 41323411151 |
11 | 16585a96470 |
12 | 80131630bb |
13 | 3b872c6499 |
14 | 2000264251 |
15 | 111cc9da1b |
hex | 99f1136cf |
41323411151 has 16 divisors (see below), whose sum is σ = 45172712448. Its totient is φ = 37489646400.
The previous prime is 41323411093. The next prime is 41323411211. The reversal of 41323411151 is 15111432314.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41323411151 is a prime.
It is a super-2 number, since 2×413234111512 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 41323411151.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41323411751) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18722690 + ... + 18724896.
It is an arithmetic number, because the mean of its divisors is an integer number (2823294528).
Almost surely, 241323411151 is an apocalyptic number.
41323411151 is a deficient number, since it is larger than the sum of its proper divisors (3849301297).
41323411151 is a wasteful number, since it uses less digits than its factorization.
41323411151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4942.
The product of its digits is 1440, while the sum is 26.
Adding to 41323411151 its reverse (15111432314), we get a palindrome (56434843465).
The spelling of 41323411151 in words is "forty-one billion, three hundred twenty-three million, four hundred eleven thousand, one hundred fifty-one".
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