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41331134041 is a prime number
BaseRepresentation
bin100110011111100001…
…110000111001011001
310221200102211011010021
4212133201300321121
51134121232242131
630553125350441
72662136562031
oct463741607131
9127612734107
1041331134041
111658a39081a
128015868421
133b88a9b742
1420012b48c1
15111d7c6e11
hex99f870e59

41331134041 has 2 divisors, whose sum is σ = 41331134042. Its totient is φ = 41331134040.

The previous prime is 41331134023. The next prime is 41331134069. The reversal of 41331134041 is 14043113314.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25203150025 + 16127984016 = 158755^2 + 126996^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41331134041 is a prime.

It is a super-2 number, since 2×413311340412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41331133997 and 41331134015.

It is not a weakly prime, because it can be changed into another prime (41331134011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20665567020 + 20665567021.

It is an arithmetic number, because the mean of its divisors is an integer number (20665567021).

Almost surely, 241331134041 is an apocalyptic number.

It is an amenable number.

41331134041 is a deficient number, since it is larger than the sum of its proper divisors (1).

41331134041 is an equidigital number, since it uses as much as digits as its factorization.

41331134041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 41331134041 its reverse (14043113314), we get a palindrome (55374247355).

The spelling of 41331134041 in words is "forty-one billion, three hundred thirty-one million, one hundred thirty-four thousand, forty-one".