Base | Representation |
---|---|
bin | 100110011111101001… |
… | …101010110001111101 |
3 | 10221200120201102111201 |
4 | 212133221222301331 |
5 | 1134122300044031 |
6 | 30553242015501 |
7 | 2662163312113 |
oct | 463751526175 |
9 | 127616642451 |
10 | 41333206141 |
11 | 165905765a7 |
12 | 80164a7591 |
13 | 3b89345936 |
14 | 2001693ab3 |
15 | 111da85d61 |
hex | 99fa6ac7d |
41333206141 has 2 divisors, whose sum is σ = 41333206142. Its totient is φ = 41333206140.
The previous prime is 41333206129. The next prime is 41333206147. The reversal of 41333206141 is 14160233314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36284535225 + 5048670916 = 190485^2 + 71054^2 .
It is a cyclic number.
It is not a de Polignac number, because 41333206141 - 215 = 41333173373 is a prime.
It is a super-2 number, since 2×413332061412 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41333206147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20666603070 + 20666603071.
It is an arithmetic number, because the mean of its divisors is an integer number (20666603071).
Almost surely, 241333206141 is an apocalyptic number.
It is an amenable number.
41333206141 is a deficient number, since it is larger than the sum of its proper divisors (1).
41333206141 is an equidigital number, since it uses as much as digits as its factorization.
41333206141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 41333206141 its reverse (14160233314), we get a palindrome (55493439455).
The spelling of 41333206141 in words is "forty-one billion, three hundred thirty-three million, two hundred six thousand, one hundred forty-one".
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